1828 United States presidential election in Massachusetts

1828 United States presidential election in Massachusetts

← 1824 October 31 – December 2, 1828 1832 →
Turnout25.7%[1] Decrease 3.3 pp
 
Nominee John Quincy Adams Andrew Jackson
Party National Republican Democratic
Home state Massachusetts Tennessee
Running mate Richard Rush John C. Calhoun
Electoral vote 15 0
Popular vote 29,836 6,012
Percentage 76.36% 15.39%

County Results

President before election

John Quincy Adams
National Republican Party

Elected President

Andrew Jackson
Democratic Party

The 1828 United States presidential election in Massachusetts took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose 15 representatives, or electors to the Electoral College, who voted for President and Vice President.

Massachusetts voted for the National Republican candidate, incumbent president John Quincy Adams, over the Democratic candidate, Andrew Jackson. Adams won Massachusetts by a landslide margin of 60.97%.

With 76.36% of the popular vote, Adams' home state would prove to be his second strongest victory in the 1828 election after neighboring Rhode Island.[2]

  1. ^ Bicentennial Edition: Historical Statistics of the United States, Colonial Times to 1970, part 2, p. 1072.
  2. ^ "1828 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.

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