1840 United States presidential election in Maryland

1840 United States presidential election in Maryland

← 1836 October 30 - December 2, 1840 1844 →
 
Nominee William Henry Harrison Martin Van Buren
Party Whig Democratic
Home state Ohio New York
Running mate John Tyler none
Electoral vote 10 0
Popular vote 33,528 28,752
Percentage 53.83% 46.17%

County Results

President before election

Martin Van Buren
Democratic

Elected President

William Henry Harrison
Whig

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The 1840 United States presidential election in Maryland took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose 10 representatives, or electors to the Electoral College, who voted for President and Vice President.

Maryland voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren, by a margin of 7.66%. As of 2020, this remains the only time in history that an incumbent Democratic president who served a full term has failed to carry any of Maryland's electoral votes in a reelection bid.[1]

This was the first presidential election that Carroll County was able to vote in.

  1. ^ "Historical U.S. Presidential Elections 1789-2020 - 270toWin". 270toWin.com. Retrieved October 28, 2022.

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