1842 Connecticut gubernatorial election

1842 Connecticut gubernatorial election

← 1841 April 4, 1842 1843 →
 
Nominee Chauncey Fitch Cleveland William W. Ellsworth
Party Democratic Whig
Electoral vote 139 68
Popular vote 25,564 23,790
Percentage 49.94% 46.29%

Cleveland:      40–50%      50–60%      60–70%      70–80%
Ellsworth:      40–50%      50–60%      60–70%      70–80%
     Tie

Governor before election

William W. Ellsworth
Whig

Elected Governor

Chauncey Fitch Cleveland
Democratic

The 1842 Connecticut gubernatorial election was held on April 4, 1842.[1][2] Former Speaker of the Connecticut House of Representatives and Democratic nominee Chauncey Fitch Cleveland was elected, defeating incumbent governor and Whig nominee William W. Ellsworth with 49.94% of the vote.

Cleveland won a plurality of the vote, but fell just short of a majority, by 107 votes. The state constitution at the time required the Connecticut General Assembly decide the election if no candidate won a majority of the vote. The state legislature voted 139 to 68 to elect Cleveland the governor.[3]

This was the first appearance of the Liberty Party in a Connecticut governor's race, and the first of Francis Gillette's ten attempts at seeking the governorship.

  1. ^ "The State election in Connecticut". Herald of the times. Newport, R.I. April 7, 1842. p. 3. Retrieved May 1, 2022.
  2. ^ "Connecticut election". The Madisonian. Washington, D.C. April 7, 1842. p. 3. Retrieved May 1, 2022.
  3. ^ "https://www.nga.org/governor/chauncey-fitch-cleveland/ Gov. Chauncey Fitch Cleveland", National Governors Association, retrieved 09-17-2020

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