1860 United States presidential election in Massachusetts

1860 United States presidential election in Massachusetts

← 1856 November 2, 1860 1864 →
Turnout65.8%[1] Decrease 4.0 pp
 
Nominee Abraham Lincoln Stephen A. Douglas John Bell
Party Republican Democratic Constitutional Union
Home state Illinois Illinois Tennessee
Running mate Hannibal Hamlin Herschel V. Johnson Edward Everett
Electoral vote 13 0 0
Popular vote 106,684 34,370 22,331
Percentage 62.80% 20.23% 13.15%

County Results
Lincoln
  40-50%
  50-60%
  60-70%
  70-80%
  80-90%


President before election

James Buchanan
Democratic

Elected President

Abraham Lincoln
Republican

The 1860 United States presidential election in Massachusetts took place on November 2, 1860, as part of the 1860 United States presidential election. Voters chose 13 electors of the Electoral College, who voted for president and vice president.

Massachusetts was won by Republican candidate Abraham Lincoln, who won the state by 42.57%.

With 62.80% of the popular vote, Massachusetts would prove to be Lincoln's third strongest state in the 1860 election in terms of popular vote percentage after neighboring Vermont and Minnesota.[2]

  1. ^ Bicentennial Edition: Historical Statistics of the United States, Colonial Times to 1970, part 2, p. 1072.
  2. ^ "1860 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.

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