1884 United States presidential election in Pennsylvania

1884 United States presidential election in Pennsylvania

← 1880 November 4, 1884 1888 →
 
Nominee James G. Blaine Grover Cleveland
Party Republican Democratic
Home state Maine New York
Running mate John A. Logan Thomas A. Hendricks
Electoral vote 30 0
Popular vote 478,804 392,785
Percentage 52.97% 43.46%

County Results

President before election

Chester A. Arthur
Republican

Elected President

Grover Cleveland
Democratic

The 1884 United States presidential election in Pennsylvania took place on November 4, 1884, as part of the 1884 United States presidential election. Voters chose thirty representatives, known as electors, to the Electoral College, who voted for president and vice president.

Pennsylvania voted for the Republican nominee, James G. Blaine, over the Democratic nominee, Grover Cleveland. Blaine won Pennsylvania by a margin of 9.51%.

This election was the first since the 1824 United States presidential election in Pennsylvania that the national winner of the election did not carry Pennsylvania, and the first time since 1796 that Pennsylvania voted for a candidate who lost both the electoral and national popular vote. (In 1824, Pennsylvania cast its vote for Andrew Jackson, who won the popular vote but lost in the contingent house election.) This was also the first time that a Democrat won without carrying the state.


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