1892 United States presidential election in Nebraska

1892 United States presidential election in Nebraska

← 1888 November 8, 1892 1896 →

Nominee Benjamin Harrison James B. Weaver Grover Cleveland Party Republican Populist Democratic Home state Indiana Iowa New York Running mate Whitelaw Reid James G. Field Adlai Stevenson I Electoral vote 8 0 0 Popular vote 87,213 83,134 24,943 Percentage 43.56% 41.53% 12.46%

County Results Harrison   30-40%   40-50%   50-60%   60-70% Weaver   30-40%   40-50%   50-60%   60-70% Cleveland   30-40%

President before election Benjamin Harrison Republican Elected President Grover Cleveland Democratic

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The 1892 United States presidential election in Nebraska took place on November 8, 1892. All contemporary 44 states were part of the 1892 United States presidential election. Voters chose eight electors to the Electoral College, which selected the president and vice president.

Nebraska was won by the Republican nominees, incumbent President Benjamin Harrison of Indiana and his running mate Whitelaw Reid of New York. Harrison and Reid narrowly defeated the Populist nominees, James B. Weaver of Iowa and his running mate James G. Field of Virginia, with national winner and Democratic nominees Grover Cleveland and Adlai Stevenson I a distant third and carrying only Thomas County by plurality.^[1]

Alongside 1908, this is one of only two elections where Nebraska did not vote the same as neighboring Kansas,^[a] and Weaver's is the best-ever third party performance in Nebraska presidential election history.

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