1908 Iowa Senate election

1908 Iowa Senate election

← 1906 November 3, 1908 1910 →

29 out of 50 seats in the Iowa Senate
26 seats needed for a majority
  Majority party Minority party
 
Party Republican Democratic
Last election 36 14
Seats after 34 16
Seat change Decrease2 Increase2

Results
     Democratic gain      Republican gain
     Democratic hold      Republican hold

The 1908 Iowa Senate elections took place as part of the biennial 1908 United States elections. Iowa voters elected state senators in 29 of the senate's 50 districts. State senators serve four-year terms in the Iowa Senate.

A statewide map of the 50 state Senate districts in the 1908 elections is provided by the Iowa General Assembly here.

The 1908 elections were the first in Iowa with primary elections due to the enactment of the Primary Election Law by the General Assembly in 1907.[1] The primary election on June 2, 1908, determined which candidates would appear on the general election ballot on November 3, 1908.[2][3]

Following the previous election, Republicans had control of the Iowa Senate with 36 seats to Democrats' 14 seats.

To claim control of the chamber from Republicans, the Democrats needed to net 12 Senate seats.

Republicans maintained control of the Iowa State Senate following the 1908 general election with the balance of power shifting to Republicans holding 34 seats and Democrats having 16 seats (a net gain of 2 seats for Democrats).

  1. ^ "Primary Election Law" (PDF). Iowa General Assembly. Retrieved June 17, 2021.
  2. ^ "Primary Election 1908 For State Senator" (PDF). Iowa General Assembly. Retrieved June 17, 2021.
  3. ^ "General Election 1908 For State Senator" (PDF). Iowa General Assembly. Retrieved June 17, 2021.

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