1908 United States presidential election in Maine

1908 United States presidential election in Maine

← 1904 November 3, 1908 1912 →
 
Nominee William Howard Taft William Jennings Bryan
Party Republican Democratic
Home state Ohio Nebraska
Running mate James S. Sherman John W. Kern
Electoral vote 6 0
Popular vote 66,987 35,403
Percentage 63.00% 33.29%

County Results
Taft
  50-60%
  60-70%
  70-80%


President before election

Theodore Roosevelt
Republican

Elected President

William Howard Taft
Republican

The 1908 United States presidential election in Maine took place on November 3, 1908, as part of the 1908 United States presidential election. Voters chose six representatives, or electors to the Electoral College, who voted for president and vice president.

Maine voted for the Republican nominees, Secretary of War William Howard Taft of Ohio and his running mate James S. Sherman of New York. They defeated the Democratic nominees, former U.S. Representative William Jennings Bryan of Nebraska and his running mate John W. Kern of Indiana.. Taft won the state by a margin of 29.71%.

With 63% of the popular vote, Maine would be Taft's second strongest victory in terms of percentage in the popular vote after nearby Vermont.[1]

Bryan had previously lost Maine to William McKinley in both 1896 and 1900.

  1. ^ "1908 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.

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