1920 United States presidential election in Iowa

1920 United States presidential election in Iowa

← 1916 November 2, 1920 1924 →

Nominee Warren G. Harding James M. Cox Party Republican Democratic Home state Ohio Ohio Running mate Calvin Coolidge Franklin D. Roosevelt Electoral vote 13 0 Popular vote 634,674 227,921 Percentage 70.91% 25.46%

County Results Harding   50-60%   60-70%   70-80%   80-90%

President before election Woodrow Wilson Democratic Elected President Warren G. Harding Republican

Elections in Iowa
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v t e

The 1920 United States presidential election in Iowa took place on November 2, 1920, as part of the 1920 United States presidential election which was held throughout all contemporary 48 states. Voters chose 13 representatives, or electors to the Electoral College, who voted for president and vice president.

Iowa voted for the Republican nominee, Senator Warren G. Harding of Ohio, over the Democratic nominee, Governor James M. Cox of Ohio. Harding ran with Governor Calvin Coolidge of Massachusetts, while Cox ran with Assistant Secretary of the Navy Franklin D. Roosevelt of New York. Harding won the state by a margin of 45.45%.

With 70.91 percent of the popular, Iowa would prove to be Harding's fifth strongest state in the 1920 election terms of popular vote percentage after North Dakota, Vermont, Michigan, and Wisconsin.^[1] Harding's performance is, by a margin of 6.79 percent, the best by any candidate in Iowa presidential election history,^[2] and he and Dwight D. Eisenhower in 1952 are the only presidential candidates to sweep all of Iowa's counties.