1940 United States presidential election in Missouri

1940 United States presidential election in Missouri
Roosevelt 50-60% 60-70% 70-80% 80-90%	Willkie 50-60% 60-70% 70-80% 80-90%
President before election; Franklin D. Roosevelt; Democratic	Elected President ; Franklin D. Roosevelt; Democratic

The 1940 United States presidential election in Missouri took place on November 5, 1940, as part of the 1940 United States presidential election. Voters chose 15^[2] representatives, or electors, to the Electoral College, who voted for president and vice president.

Missouri was won by incumbent President Franklin D. Roosevelt (D–New York), running with Secretary Henry A. Wallace, with 52.27 percent of the popular vote, against Wendell Willkie (R–New York), running with Minority Leader Charles L. McNary, with 47.50 percent of the popular vote.^[3]^[4]

Despite his victory, Roosevelt carried Missouri by a greatly reduced margin than he had four years prior, defeating Wilkie by less than five percentage points, In 1936, Roosevelt had defeated Alf Landon in the state by more than 22 percentage points and with over 60% of the vote.

^ "United States Presidential election of 1940 — Encyclopædia Britannica". Retrieved August 21, 2018.
^ "1940 Election for the Thirty-ninth Term (1941-45)". Retrieved August 21, 2018.
^ "1940 Presidential General Election Results — Missouri". Retrieved August 21, 2018.
^ "The American Presidency Project — Election of 1940". Retrieved August 21, 2018.

[1] "United States Presidential election of 1940 — Encyclopædia Britannica". Retrieved August 21, 2018.

[2] "1940 Election for the Thirty-ninth Term (1941-45)". Retrieved August 21, 2018.

[3] "1940 Presidential General Election Results — Missouri". Retrieved August 21, 2018.

[4] "The American Presidency Project — Election of 1940". Retrieved August 21, 2018.

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