1948 United States presidential election in Kentucky

1948 United States presidential election in Kentucky

← 1944 November 2, 1948[1] 1952 →

All 11 Kentucky votes to the Electoral College
 
Nominee Harry S. Truman Thomas E. Dewey
Party Democratic Republican
Home state Missouri New York
Running mate Alben W. Barkley Earl Warren
Electoral vote 11 0
Popular vote 466,756 341,210
Percentage 56.74% 41.48%

County results

President before election

Harry S. Truman
Democratic

Elected President

Harry S. Truman
Democratic

The 1948 United States presidential election in Kentucky took place on November 2, 1948, as part of the 1948 United States presidential election. Kentucky voters chose 11[2] representatives, or electors, to the Electoral College, who voted for president and vice president.

Kentucky was won by incumbent President Harry S. Truman (DMissouri), running with Senator Alben W. Barkley, with 56.74 percent of the popular vote, against Governor Thomas E. Dewey (RNew York), running with Governor Earl Warren, with 41.48 percent of the popular vote.[3][4]

Dewey performed worse than he had four years previously, with both his margin of loss increasing, and the percentage of the vote he received decreasing, even as he fared much better nationally than he had four years prior. This discrepancy was at least in part due to the choice of President Truman's running mate, Senator Barkley, who himself came from Kentucky.

  1. ^ "United States Presidential election of 1948 – Encyclopædia Britannica". Retrieved October 30, 2017.
  2. ^ "1948 Election for the Forty-First Term (1949-53)". Retrieved October 30, 2017.
  3. ^ "1948 Presidential General Election Results – Kentucky". Retrieved October 30, 2017.
  4. ^ "The American Presidency Project – Election of 1948". Retrieved October 30, 2017.

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