1992 United States presidential election in Alabama

1992 United States presidential election in Alabama

← 1988 November 3, 1992 1996 →
 
Nominee George H. W. Bush Bill Clinton Ross Perot
Party Republican Democratic Independent
Home state Texas Arkansas Texas
Running mate Dan Quayle Al Gore James Stockdale
Electoral vote 9 0 0
Popular vote 804,283 690,080 183,109
Percentage 47.65% 40.88% 10.85%

County Results

President before election

George H. W. Bush
Republican

Elected President

Bill Clinton
Democratic

The 1992 United States presidential election in Alabama took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose nine representatives, or electors to the Electoral College, who voted for president and vice president.

Alabama was won by President George H. W. Bush (R-TX). The presidential contest in Alabama was not a surprise, with Bush winning 47.65% to 40.88% over Arkansas Governor Bill Clinton (D), a margin of 6.77%. Despite the fact that Clinton was a Southern Democrat, Alabama remained a reliably Republican state. The last Democrat to carry Alabama was Jimmy Carter in 1976, who was also a Southern Democrat.[1] Billionaire businessman Ross Perot (I-TX) finished in third, with a disappointing 10.85%.[1]

  1. ^ a b "Dave Leip's Atlas of U.S. Presidential Elections".

Developed by StudentB